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100=30t+1.75t^2
We move all terms to the left:
100-(30t+1.75t^2)=0
We get rid of parentheses
-1.75t^2-30t+100=0
a = -1.75; b = -30; c = +100;
Δ = b2-4ac
Δ = -302-4·(-1.75)·100
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-40}{2*-1.75}=\frac{-10}{-3.5} =2+1/1.1666666666667 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+40}{2*-1.75}=\frac{70}{-3.5} =-20 $
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